document.write( "Question 183921: please show me how to factor a polynomial completely thank you\r
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\n" ); document.write( "\n" ); document.write( " -36a2b+21ab2-3b3\r
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Algebra.Com's Answer #137985 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Factor completely: Note: You can indicate exponents by use of the caret symbol (^). Example - a-squared would look like a^2
\n" ); document.write( "\"-36a%5E2b%2B21ab%5E2-3b%5E3\" First factor out those factors that are common to each term, in this case, I would factor out -3b thus:
\n" ); document.write( "\"-3b%2812a%5E2-7ab%2Bb%5E2%29\" Notice the change of sign on each factor when you factor the -3.
\n" ); document.write( "Now to factor the trinomial in parentheses, first look at the leading term, (\"12a%5E2\"), and note that this can be factored as:
\n" ); document.write( "\"12a%5E2+=+1%2A12%2Aa%2Aa\" or \"-1%2A-12%2Aa%2Aa\"
\n" ); document.write( "\"12a%5E2+=+2%2A6%2Aa%2Aa\" or \"-2%2A-6%2Aa%2Aa\"
\n" ); document.write( "\"12a%5E2+=+3%2A4%2Aa%2Aa\" or \"highlight%28-3%2A-4%2Aa%2Aa%29\"
\n" ); document.write( "Now notice the middle term, \"-7ab\" The only way to factor this is:
\n" ); document.write( "\"-7ab+=+-7%2Aa%2Ab\" and you can get \"-7\" by adding \"highlight%28-3%2B%28-4%29%29\" and the last term \"b%5E2\" can only be factored as \"highlight%28b%2Ab%29\"
\n" ); document.write( "So putting it all together, you get:
\n" ); document.write( "\"-36a%5E2b%2B21ab%5E2-3b%5E3+=+highlight%28-3b%283a-b%29%284a-b%29%29\"
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