document.write( "Question 183825: The sum of an integer and three times the next consecutive integer is 47. What is the original integer. \n" ); document.write( "
Algebra.Com's Answer #137930 by halbren(10)![]() ![]() ![]() You can put this solution on YOUR website! x is the first integer and x+1 is the next \n" ); document.write( "By the question \n" ); document.write( "x+3(x+1)=47 \n" ); document.write( "Distribute \n" ); document.write( "x+3x+3=47 \n" ); document.write( "Combine the variables \n" ); document.write( "4x+3=47 \n" ); document.write( "Subtract 3 from both sides \n" ); document.write( "4x=44 \n" ); document.write( "Divide both sides by 4 \n" ); document.write( "x=44/4=11\r \n" ); document.write( "\n" ); document.write( "If x=11 then x+1=12\r \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "x+3(x+1)=11+3(12)=11+36=47\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |