document.write( "Question 183825: The sum of an integer and three times the next consecutive integer is 47. What is the original integer. \n" ); document.write( "
Algebra.Com's Answer #137930 by halbren(10)\"\" \"About 
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x is the first integer and x+1 is the next
\n" ); document.write( "By the question
\n" ); document.write( "x+3(x+1)=47
\n" ); document.write( "Distribute
\n" ); document.write( "x+3x+3=47
\n" ); document.write( "Combine the variables
\n" ); document.write( "4x+3=47
\n" ); document.write( "Subtract 3 from both sides
\n" ); document.write( "4x=44
\n" ); document.write( "Divide both sides by 4
\n" ); document.write( "x=44/4=11\r
\n" ); document.write( "\n" ); document.write( "If x=11 then x+1=12\r
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "x+3(x+1)=11+3(12)=11+36=47\r
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