document.write( "Question 183783: I am absolutely baffled by this one. I am terrible at fractions anyway, but that to a word problem and I am lost.\r
\n" ); document.write( "\n" ); document.write( "A goldsmith has two alloys that are different purities of gold. The first is three-fourths pure gold and the second is five-twelfths pure gold. How many ounces of each should be melted and mixed in order to otain a 6 ounce mixture that is two-thirds pure gold?
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Algebra.Com's Answer #137911 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A goldsmith has two alloys that are different purities of gold. The first is three-fourths pure gold and the second is five-twelfths pure gold. How many ounces of each should be melted and mixed in order to otain a 6 ounce mixture that is two-thirds pure gold?
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\n" ); document.write( "Equation:
\n" ); document.write( "gold + gold = gold
\n" ); document.write( "(3/4)x + (5/12)(6-x) = (2/3)*6\r
\n" ); document.write( "\n" ); document.write( "Multiply thru by 12 to get:
\n" ); document.write( "9x + 5(6-x) = 8*6\r
\n" ); document.write( "\n" ); document.write( "9x + 5*6 - 5x = 8*6\r
\n" ); document.write( "\n" ); document.write( "4x = 3*6\r
\n" ); document.write( "\n" ); document.write( "x = 9/2 = 4 1/2 oz (amt. of (3/4) pure gold in the mixture)\r
\n" ); document.write( "\n" ); document.write( "6-x = 6 - 4 1/2 = 1 1/2 oz (amt of (5/12) pure gold in the mixture)\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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