document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=183765>Question 183765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Johnson Farm has 500 acres of land allotted for cultivating corn and wheat.<BR>\n" );
document.write( "The cost of cultivating corn and wheat is $42 and $30 pre acre respectively.<BR>\n" );
document.write( "Mr.Johnson has $18,600 available for cultivating these corp.<BR>\n" );
document.write( "If he used all the land and entire budget,how many acres of each crop should he plant? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137902 by </B><A HREF=/tutors/aboutme.mpl?userid=math_il><B>math_il(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_il><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let c = no of acres of corn and w = no of acres of wheat<BR>\n" );
document.write( "using the total acres, we get<BR>\n" );
document.write( "c +w =500 or w = 500-c (A)<BR>\n" );
document.write( "using the cost of cultivation, we get<BR>\n" );
document.write( "42c +30w = 18600<BR>\n" );
document.write( "substitute the value of w from equation A<BR>\n" );
document.write( "42c + 30(500-c) = 18600<BR>\n" );
document.write( "42c +15000 -30c =18600<BR>\n" );
document.write( "12c = 18600-15000 = 3600<BR>\n" );
document.write( "c = 3600/12 = 300 acres<BR>\n" );
document.write( "and use this in A , w = 500 -c = 500 -300 = 200 acres<BR>\n" );
document.write( "so answer is 300 acres of corn and 200 acres of wheat </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );