document.write( "Question 183757: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks? \n" ); document.write( "
Algebra.Com's Answer #137900 by ptaylor(2198)\"\" \"About 
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Steven mixes drinks at the rate of 4 drinks per min
\n" ); document.write( "Sue mixes drinks at the rate of 2 drinks per min
\n" ); document.write( "Jack mixes drinks at the rate of (4/3) drinks per min
\n" ); document.write( "Together they mix drinks at the rate of 4+2+(4/3)=12/3 +6/3+4/3=22/3 drinks per min
\n" ); document.write( "Let x=amount of time it takes all three working together to mix 20 drinks
\n" ); document.write( "Then all three mixes drinks at the rate of 20/x drinks per min
\n" ); document.write( "So, our equation to solve is:
\n" ); document.write( "22/3 = 20/x or
\n" ); document.write( "22x=60
\n" ); document.write( "x=2.73 min---------------amount of time it takes all three working together to mix 20 drinks\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "4*(2.73)+2*(2.73)+(4/3)(2.73)=20
\n" ); document.write( "10.9 +5.5+3.6=20
\n" ); document.write( "20=20\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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