document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=25678>Question 25678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Freight train is traveling 30milesper hour. An automobile starts out from the same place 1 hour later and overtakes the traimnin 3 hours. What was the rate of the automobile. could you work this one out step by step. i would appreciate it so so so so much. thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13788 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13788\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEE FOLLOWING EXAMPLES WHICH ARE SIMILAR AND TRY. IF YOU STILL HAVE PROBLEM COME BACK<BR>\n" );
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document.write( "A motorboat starts out and travels 9 miles an hour. In 3 hours another motorboat rraveling 18 miles an hour starts out to overtake the first one. In how many hours will thei sceond boat overtake the first.<BR>\n" );
document.write( "1 solutions<BR>\n" );
document.write( "Answer 13785 by venugopalramana(735) About Me  on 2006-01-27 00:19:56 (Show Source):<BR>\n" );
document.write( "A motorboat starts out and travels 9 miles an hour. In 3 hours another motorboat rraveling 18 miles an hour starts out to overtake the first one. In how many hours will thei sceond boat overtake the first.<BR>\n" );
document.write( "RELATIVE SPEED WHILE TRAVELLING IN SAME DIRECTIONS = S2-S1=18-9=9 MPH.<BR>\n" );
document.write( "INITIAL DISTANCE OF SEPERATION = DISTANCE TRAVELLED BY FIRST BOAT IN 3 HOURS<BR>\n" );
document.write( "= 3*9=27 MILES.<BR>\n" );
document.write( "FINAL DISTANCE OF SEPERATION=0<BR>\n" );
document.write( "HENCE DISTANCE TO BE COVERED WHEN BOTH BOATS ARE TRAVELLING IN SAME DIRECTION =27-0=27<BR>\n" );
document.write( "TIME TAKEN =DISTANCE / RELATIVE SPEED = 27 / 9 = 3 HRS.\r<BR>\n" );
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document.write( "Travel_Word_Problems/25659: C and D start from two points 480 miles apart and travel toward eash other. They meet in 8 hours. If C travels 6 miles per hour faster than D, find their rates.<BR>\n" );
document.write( "1 solutions<BR>\n" );
document.write( "Answer 13784 by venugopalramana(735) About Me  on 2006-01-27 00:06:59 (Show Source):<BR>\n" );
document.write( "SEE THE FOLLOWING PROBLEM WHICH IS SIMILAR<BR>\n" );
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document.write( "Two men, A and B, start toward each other at the same time from points 510 miles apart. If they travel 40 and 4 milea an hour respectively, in how many hours will they meet.<BR>\n" );
document.write( "RELATIVE SPEED WHILE TRAVELLING IN OPPOSITE DIRECTION TO EACH OTHER = S1+S2=40+4=44 MPH.<BR>\n" );
document.write( "INTIAL DISTANCE OF SEPERATION =510 MILES.<BR>\n" );
document.write( "FINAL DISTANCE OF SEPERATION =0<BR>\n" );
document.write( "HENCE DISTANCE TO BE COVERED TOGETHER = 510 -0 =510 MILES<BR>\n" );
document.write( "TIME NEEDED =DISTANCE / RELATIVE SPEED = 510/44 HRS<BR>\n" );
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document.write( "IN YOU CASE ,WE GET..WITH X AND X+6 SPEEDS AS GIVEN,<BR>\n" );
document.write( "8= 480/(X+X+6)<BR>\n" );
document.write( "8(2X+6)=480<BR>\n" );
document.write( "2X+6=480/8=60<BR>\n" );
document.write( "2X=60-6=54<BR>\n" );
document.write( "54/2=27.<BR>\n" );
document.write( "HENCE THEIR SPEEDS ARE 27 AND 33 MPH.\r<BR>\n" );
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document.write( "Travel_Word_Problems/25660: Two men, A and B, start toward each other at t </SPAN>\n" );
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