document.write( "Question 183638This question is from textbook Algebra
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document.write( ": A sailboat travels 20 miles downstream in three hours. It returns in four hours. Find the speed of the sailboat in still water AND the rate of the current. \n" );
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Algebra.Com's Answer #137877 by halbren(10)![]() ![]() ![]() You can put this solution on YOUR website! This is a speed and distance problem. The assumption here is the speed of the sailboat is the same in both direction. The current however will help travel downstream and low travel upstream. The distance travelled in each direction will be the same. \n" ); document.write( " \n" ); document.write( "downstream would be \n" ); document.write( " \n" ); document.write( "coming back upstream \n" ); document.write( " \n" ); document.write( "If we solve the second equation for s we get \n" ); document.write( " \n" ); document.write( "Divide both sides by 4 \n" ); document.write( " \n" ); document.write( "Simplify \n" ); document.write( " \n" ); document.write( "Using substitution, replace s with 5+c in first equation \n" ); document.write( " \n" ); document.write( "Distribute to remove parenthesis \n" ); document.write( " \n" ); document.write( "Move constants to one side and combined like variables \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "divide both sides by 6 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Put this value for c back into s=5+c \n" ); document.write( " |