document.write( "Question 183669: I NEED HELP SOLVING THIS WORD PROBLEM. I DID TRY SOMETHING BUT I DON'T THINK IT IS RIGHT. THE QUESTION IS \"the length of a rectangular is 5 more than twice its width. it's perimeter is 88 feet. find it's dimensions?\" THIS IS WHAT I TRIED:
\n" ); document.write( "L=w+5
\n" ); document.write( "2L+2w=88
\n" ); document.write( "2(W+5)+2w=68
\n" ); document.write( "2W+10+2W=68
\n" ); document.write( "4W=68-10
\n" ); document.write( "4W=58
\n" ); document.write( "W=58/4
\n" ); document.write( "W=14.5
\n" ); document.write( "L=15.5+5=20.5 INCHES \n" ); document.write( "

Algebra.Com's Answer #137862 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
\"the length of a rectangular is 5 more than twice its width. it's perimeter is 88 feet. find it's dimensions
\n" ); document.write( "---------------------
\n" ); document.write( "Perimeter = 2(L + W)
\n" ); document.write( "88 = 2((2W+5) + W)\r
\n" ); document.write( "\n" ); document.write( "44 = (3W + 5)\r
\n" ); document.write( "\n" ); document.write( "3W = 39\r
\n" ); document.write( "\n" ); document.write( "W = 13 feet (Width)
\n" ); document.write( "-----------------
\n" ); document.write( "L = 2W + 5
\n" ); document.write( "L = 2*13 + 5
\n" ); document.write( "L = 31 feet (Length)\r
\n" ); document.write( "\n" ); document.write( "==============================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

\n" );