document.write( "Question 183609: A 2\" square is cut from each corner of a rectangler piece of sheet metal. The metal is bent up to form a box with no top. The length of the box is 5\" more than the width. The volume of the box is 168 in^3.\r
\n" ); document.write( "\n" ); document.write( "Find: the surface area of the box?
\n" ); document.write( "note: Define var. define other quantities as needed, write a quadratic equation in one var., solve.
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Algebra.Com's Answer #137831 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"w\" in = the width of the box
\n" ); document.write( "Let \"V\" in3 = volume of the box
\n" ); document.write( "given:
\n" ); document.write( "length = \"w+%2B+5\" in
\n" ); document.write( "height = \"2\" in
\n" ); document.write( "\"V+=+168\" in3
\n" ); document.write( "------------------------
\n" ); document.write( "\"V+=+w%2A%28w+%2B+5%29%2A2\"
\n" ); document.write( "\"V+=+2%2A%28w%5E2+%2B+5w%29\"
\n" ); document.write( "\"V+=+2w%5E2+%2B+10w\"
\n" ); document.write( "\"168+=+2w%5E2+%2B+10w\"
\n" ); document.write( "\"2w%5E2+%2B+10w+-+168+=+0\"
\n" ); document.write( "\"w%5E2+%2B+5w+-+84+=+0\"
\n" ); document.write( "Solve using quadratic formula
\n" ); document.write( "\"w+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"a+=+1\"
\n" ); document.write( "\"b+=+5\"
\n" ); document.write( "\"c+=+-84\"
\n" ); document.write( "\"w+=+%28-5+%2B-+sqrt%28+5%5E2-4%2A1%2A%28-84%29+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"w+=+%28-5+%2B-+sqrt%28+25+%2B+336+%29%29%2F2+\"
\n" ); document.write( "\"w+=+%28-5+%2B-+sqrt%28+361+%29%29%2F2+\"
\n" ); document.write( "\"w+=+%28-5+%2B-+19%29%2F2+\"
\n" ); document.write( "\"w+=+-12\" Can't use a negative value here
\n" ); document.write( "\"w+=+7\"
\n" ); document.write( "and
\n" ); document.write( "\"w+%2B+5+=+12\"
\n" ); document.write( "If I flatten out the box and put the 4 square cut-outs from
\n" ); document.write( "the corners back, then 4 inches gets added to the width
\n" ); document.write( "and 4 inches to the length.
\n" ); document.write( "\"w+%2B+4\" is the width of flattened box
\n" ); document.write( "\"w+%2B+5+%2B+4\" is the length of the flattened box
\n" ); document.write( "Area = \"%287+%2B+4%29%2A%287+%2B+5+%2B+4%29\"
\n" ); document.write( "Area = \"11%2A16\"
\n" ); document.write( "Area = \"176\" in2
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