document.write( "Question 183580: How many liters of a 60% alcohol solution should be mixed with 30 liters of a 40% solution in order to get a 55% solution? \n" ); document.write( "
Algebra.Com's Answer #137802 by stanbon(75887)\"\" \"About 
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How many liters of a 60% alcohol solution should be mixed with 30 liters of a 40% solution in order to get a 55% solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.60x + 0.40*30 = 0.55(x+30)\r
\n" ); document.write( "\n" ); document.write( "Multiply thru by 100 to get:\r
\n" ); document.write( "\n" ); document.write( "60x + 40*30 = 55x + 55*30
\n" ); document.write( "5x = 15*30
\n" ); document.write( "x = 90 liters (amt. of 60% solution required for the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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