document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=183569>Question 183569</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trains A and B are traveling in the same direction on paralle tracks. Train A is traveling at 100 mph and train B is traveling at 120 mph. Train A passes the station at 9:20 P.M.  If train B passes the same station at 9:32 P.M., at what time will train B catch up to train A? __:___ P.M. or A.M. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137793 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "THE DISTANCES ARE THE SAME THUS:<BR>\n" );
document.write( "100T=120(T-12/60)<BR>\n" );
document.write( "100T=120T-120*.2<BR>\n" );
document.write( "100T=120T-24<BR>\n" );
document.write( "100T-120T=-24<BR>\n" );
document.write( "-20T=-24<BR>\n" );
document.write( "T=-24/-20<BR>\n" );
document.write( "T=1.2 HOURS AFTER TRAIN A LEAVES THE STATION THEY WILL MEET.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "100*1.2=120(1.2-.2)<BR>\n" );
document.write( "120=120*1<BR>\n" );
document.write( "120=120 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );