document.write( "Question 183571: A certain aircraft can fly 1330 miles with the wind in 5 hours and travel the same distance against the wind in 7 hours. What is the speed of the wind? \n" ); document.write( "
Algebra.Com's Answer #137791 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "R=D/T \n" ); document.write( "R=1330/5 \n" ); document.write( "R=266 MPH WITH THE WIND. \n" ); document.write( "R=1330/7 \n" ); document.write( "R=190 MPH AGAINST THE WIND \n" ); document.write( "(266-190)/2=76/2=38 MPH IS THE WIND SPEED. \n" ); document.write( "pROOF: \n" ); document.write( "266-38=228 MPH FOR THE PLAN'S SPEED IN STILL AIR. \n" ); document.write( "190+38=228 DITTO. \n" ); document.write( " |