document.write( "Question 183571: A certain aircraft can fly 1330 miles with the wind in 5 hours and travel the same distance against the wind in 7 hours. What is the speed of the wind? \n" ); document.write( "
Algebra.Com's Answer #137791 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
D=RT
\n" ); document.write( "R=D/T
\n" ); document.write( "R=1330/5
\n" ); document.write( "R=266 MPH WITH THE WIND.
\n" ); document.write( "R=1330/7
\n" ); document.write( "R=190 MPH AGAINST THE WIND
\n" ); document.write( "(266-190)/2=76/2=38 MPH IS THE WIND SPEED.
\n" ); document.write( "pROOF:
\n" ); document.write( "266-38=228 MPH FOR THE PLAN'S SPEED IN STILL AIR.
\n" ); document.write( "190+38=228 DITTO.
\n" ); document.write( "
\n" );