document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=183490>Question 183490</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello,\r<BR>\n" );
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document.write( "Please help me. The question:\r<BR>\n" );
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document.write( "How many ounces from a 15% solution must be mixed with 4 ounces of a 20% solution to make a 17% solution?\r<BR>\n" );
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document.write( "Your help is much appreciated. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137755 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Let x=amount of 15% solution needed<BR>\n" );
document.write( "Now we know that the amount of pure stuff in the 15% solution (0.15x) plus the amount of pure stuff in the 20% solution (0.20*4) has to equal the amount of pure stuff in the final mixture (0.17(4+x)). So:\r<BR>\n" );
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document.write( "0.15x+0.20*4=0.17(4+x) get rid of parens<BR>\n" );
document.write( "0.15x+0.80=0.68+0.17x subtract 0.68 and also 0.15x from each side<BR>\n" );
document.write( "0.15x-0.15x+0.80-0.68=0.68-0.68+0.17x-0.15x collect like terms<BR>\n" );
document.write( "0.12=0.02x  divide each side by 0.02<BR>\n" );
document.write( "x=6 oz----------------------amont of 15% solution needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "0.15*6+0.20*4=0.17*10<BR>\n" );
document.write( "0.90+0.80=1.70<BR>\n" );
document.write( "1.70=1.70\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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