document.write( "Question 183468: gene rides 10 minutes to a friends house and then walks 15 minutes to the gym. he rides 10 km/hr faster than he walks and the entire distance covered is 2.75 km. how far is it from the friends house to the gym?\r
\n" ); document.write( "\n" ); document.write( "5 Step process ?!
\n" ); document.write( "let [ ] statements.... \n" ); document.write( "
Algebra.Com's Answer #137754 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
\n" ); document.write( "Let r=rate that he walks
\n" ); document.write( "Then r+10=rate that he rides
\n" ); document.write( "Distance covered riding=(r+10)*(1/6) {10 min=1/6 hr}
\n" ); document.write( "Distance covered walking=r*(1/4) (friend's house to gym)\r
\n" ); document.write( "\n" ); document.write( "Now we are told that the above two distance add up to 2.75 km, so:
\n" ); document.write( "(1/6)(r+10)+(1/4)r=2.75 multiply each term by 12
\n" ); document.write( "2(r+10)+3r=33
\n" ); document.write( "2r+20+3r=33 subtract 20 from each side
\n" ); document.write( "5r=33-20
\n" ); document.write( "5r=13
\n" ); document.write( "r=2.6 km/hr-------------rate that he walks
\n" ); document.write( "r+10=2.6+10=12.6 km/hr----rate that he rides
\n" ); document.write( "So
\n" ); document.write( "Distance from friend's house to gym=(2.6)*(1/4)=0.65 km\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "(1/6)*(12.6)+(1/4)(2.6)=2.75
\n" ); document.write( "2.1+0.65=2.75
\n" ); document.write( "2.75=2.75\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
\n" ); document.write( " \n" ); document.write( "
\n" );