document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=183510>Question 183510</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help. The length of each side of a cube is increased by 20%, what is the % increase in the surface area of the cube? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137749 by </B><A HREF=/tutors/aboutme.mpl?userid=MissionPossible><B>MissionPossible(18)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MissionPossible><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137749\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> suppose the length of the small(old) cube is X.<BR>\n" );
document.write( "The length of each side of a cube is increased by 20% ,then the length of the bigger(new) cube would be 1.2X (120% = 120*x/100 = 1.2X\r<BR>\n" );
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document.write( "The surface of the small(old) cube is 6X^2<BR>\n" );
document.write( "The surface of the bigger(new) cube is 6(1.2X)^2 = 1.44* 6X^2\r<BR>\n" );
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document.write( "Then the % increase in the surface area of the cube = 44 %  Ans\r<BR>\n" );
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