document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=25670>Question 25670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The endpint of the daimeter of a circle are at (-4,10) and (-8,0). What are the coordinates of ht ecenter of the circle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13772 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The center is at the midpoint of the diameter.  This is like the average of the x coordinates, and the average of the y coordinates.  So, add the x coordinates and divide by 2, add the y coordinates and divide by 2.\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28%28-4%29+%2B+%28-8%29%29%2F2=+-12%2F2=+-6 ALIGN=MIDDLE  ALT=\"x+=+%28%28-4%29+%2B+%28-8%29%29%2F2=+-12%2F2=+-6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%2810%2B0%29%2F2=+5 ALIGN=MIDDLE  ALT=\"y+=+%2810%2B0%29%2F2=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Coordinates of the center : (-6,5)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "R^2 at SCC\r<BR>\n" );
document.write( "\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );