document.write( "Question 183432: Determine the equation of the tangent to the curve y=((x^2)-1)/(3x) at x=2. \n" ); document.write( "
Algebra.Com's Answer #137718 by Alan3354(69443)\"\" \"About 
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Determine the equation of the tangent to the curve y=(x^2-1)/3x at x=2.
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\n" ); document.write( "y=(x^2-1)*x^-1/3 at x=2.
\n" ); document.write( "dy/dx = (1/3)*(2x*x^-1 + (x^2-1)*(-1)*(x^-2))
\n" ); document.write( "= \"%281%2F3%29%2A%282+-+%28x%5E2-1%29%2Fx%5E2%29\"
\n" ); document.write( "@ x = 2:
\n" ); document.write( "= (1/3)*(2 - 3/4)
\n" ); document.write( "= (1/3)*(5/4)
\n" ); document.write( "= 5/12
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