document.write( "Question 183384: The length of a rectangle exceeds twice its width by 4 cm. The perimeter of the rectangle is 68 cm. Find the length and the width. (Hint: P=2l+2w)\r
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document.write( "Can you please help me with this question? \n" );
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Algebra.Com's Answer #137716 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle exceeds twice its width by 4 cm. The perimeter of the rectangle is 68 cm. Find the length and the width. (Hint: P=2l+2w) \n" ); document.write( "--------------------------- \n" ); document.write( "Perimeter = 2(L + W) \n" ); document.write( "68 = 2((2W+4)+W) \n" ); document.write( "34 = 3W + 4 \n" ); document.write( "30 = 3W \n" ); document.write( "W = 10 cm (width) \n" ); document.write( "L = 2W+4 = 2*10+4 = 24 cm (length) \n" ); document.write( "===================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |