document.write( "Question 183384: The length of a rectangle exceeds twice its width by 4 cm. The perimeter of the rectangle is 68 cm. Find the length and the width. (Hint: P=2l+2w)\r
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Algebra.Com's Answer #137716 by stanbon(75887)\"\" \"About 
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The length of a rectangle exceeds twice its width by 4 cm. The perimeter of the rectangle is 68 cm. Find the length and the width. (Hint: P=2l+2w)
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\n" ); document.write( "Perimeter = 2(L + W)
\n" ); document.write( "68 = 2((2W+4)+W)
\n" ); document.write( "34 = 3W + 4
\n" ); document.write( "30 = 3W
\n" ); document.write( "W = 10 cm (width)
\n" ); document.write( "L = 2W+4 = 2*10+4 = 24 cm (length)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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