document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=183451>Question 183451</A>: <I><SPAN STYLE=\"word-break: break-all;\"> for the following equation  3x -y =4   find x if y=2  findy if x=1/3 present solutions as ordred pairs </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137711 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> for the following equation 3x -y = 4 find x if y=2 find y if x=1/3 <BR>\n" );
document.write( "Present solutions as ordred pairs<BR>\n" );
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document.write( "3x -y = 4<BR>\n" );
document.write( "Solve for \"y\": y = 3x - 4<BR>\n" );
document.write( "Solve for \"x\": x = (1/3)y + (4/3)<BR>\n" );
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document.write( "If y=2, then x = (1/3)*2 + (4/3) = (2/3)+(4/3) = (6/3) = 2<BR>\n" );
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document.write( "If x = 1/3, then y = 3*(1/3) - 4 = 1-4 = -3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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