document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=183334>Question 183334</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three tennis balls are tightly packed in a can.(circular cylinder). What fraction of the volume of the can is occupied by the tennis balls? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137703 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137703\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Three tennis balls are tightly packed in a can.(circular cylinder). What fraction of the volume of the can is occupied by the tennis balls?<BR>\n" );
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document.write( "Volume of each ball is (4/3)pi*r^3<BR>\n" );
document.write( "Total ball volume = 3(4/3)pi*r^3 = (4*pi*r^3)<BR>\n" );
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document.write( "Volume of the can:<BR>\n" );
document.write( "Area of the base = pi*r^2<BR>\n" );
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document.write( "Height of the can = 6r<BR>\n" );
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document.write( "Volume of the can 6r*pir^2 = 6pir^3<BR>\n" );
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document.write( "Desired Fraction: 6pir^3/4pir^3 = 3/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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