document.write( "Question 183408: The sum of two numbers is equal to twice their difference. If one number is 4 more than the other, find the numbers.\r
\n" ); document.write( "\n" ); document.write( "I did A=first # a=2nd #
\n" ); document.write( "Then A+a=2(A-a) A=2a+4
\n" ); document.write( " but it does not come out right.
\n" ); document.write( "Please help.\r
\n" ); document.write( "\n" ); document.write( "Anne
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Algebra.Com's Answer #137699 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let x=first number, y=second number\r
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\n" ); document.write( "\n" ); document.write( "\"The sum of two numbers is equal to twice their difference\" translates to \"x%2By=2%28x-y%29\" Note: I'm implying that \"x\" is bigger than \"y\"\r
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\n" ); document.write( "\n" ); document.write( "Also, \" If one number is 4 more than the other\" means that \"x=y%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=2%28x-y%29\" Start with the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B4%2By=2%28y%2B4-y%29\" Plug in \"x=y%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "\"2y%2B4=2%284%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"2y%2B4=8\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"2y=4\" Subtract 4 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"y=2\" Divide both sides by 2 to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"x=y%2B4\" Go back to the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%2B4\" Plug in \"y=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=6\" Add\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=6\" and \"y=2\" which means that the two numbers are 6 and 2
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