document.write( "Question 183376: How to reach the end results for x/2+1=3, 3x/2+1=4 and 2x/3+1=5. break these down please \n" ); document.write( "
Algebra.Com's Answer #137679 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Use the following process for each. We'll do the first one, then you cna use the same idea to do the other two.
\n" ); document.write( "\"x%2F2%2B1=3\" Isolate the term with x by subtracting the constant on the left (sub 1 from both sides). To get
\n" ); document.write( "\"x%2F2+=+2\" Now get x 'by itself'. In this case, multiply both sides by 2
\n" ); document.write( "\"x+=+4\"\r
\n" ); document.write( "\n" ); document.write( "For the next one
\n" ); document.write( "\"3x%2F2%2B1=4\" Isolate the term with x
\n" ); document.write( "\"3x%2F2+=+3\" Now get x 'by itself'. Multiply by 2/3
\n" ); document.write( "\"x+=+%282%2F3%29%2A3\"
\n" ); document.write( "\"x+=+2\"\r
\n" ); document.write( "\n" ); document.write( "You can do the last one
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