document.write( "Question 25630: the perimeter of a triangle measures 62cm. the 2nd side is 2 times longer than the fist, and the 3rd side is 12cm larger than the second. What is the length of the longest side. \n" ); document.write( "
Algebra.Com's Answer #13765 by Paul(988)\"\" \"About 
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Let the first side be x
\n" ); document.write( "Let the second side be y
\n" ); document.write( "Let the third side be z
\n" ); document.write( "x+y+z=62 (equation 1) (1)
\n" ); document.write( "y = 2x---->2x-y=0 (equation 2) (2)
\n" ); document.write( "z = 12+2x ----> 2x-z=-12 (equation 3) (3)
\n" ); document.write( "Eliminate z
\n" ); document.write( "x+y+z=62 (1)
\n" ); document.write( "2x-z=-12 (3)
\n" ); document.write( "-------- --> add the following
\n" ); document.write( "3x+y=50 (set 1)
\n" ); document.write( "Add set 1 to equation 2
\n" ); document.write( "3x+y=50
\n" ); document.write( "2x-y=0
\n" ); document.write( "5x=50
\n" ); document.write( "x=10\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "y=2(10)
\n" ); document.write( "y=20\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "z=2(10)+12
\n" ); document.write( "z=32\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hence, the first side 10 cm, the second side is 20 cm, and the third side is 32 cm.
\n" ); document.write( "Paul.
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