document.write( "Question 183277: The sum of two integers is twenty. Five times the smaller integer is two more than twice the larger integer. Find the two integers. \n" ); document.write( "
Algebra.Com's Answer #137649 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=smaller integer
\n" ); document.write( "And 20-x=the larger integer\r
\n" ); document.write( "\n" ); document.write( "Now we are told that:
\n" ); document.write( "5*x-2=2(20-x) get rid of parens
\n" ); document.write( "5x-2=40-2x add 2 and also 2x to each side
\n" ); document.write( "5x-2+2+2x=40+2-2x+2x collect like terms
\n" ); document.write( "7x=42 divide each side by 7
\n" ); document.write( "x=6-------------------------------smaller integer
\n" ); document.write( "20-x=20-6=14 larger integer\r
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\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "5*6-2=2*14
\n" ); document.write( "28=28\r
\n" ); document.write( "\n" ); document.write( "This could also be solved using two unknowns
\n" ); document.write( "x=smaller
\n" ); document.write( "y=larger
\n" ); document.write( "x+y=20-------------------eq1
\n" ); document.write( "5x-2=2y--------------------eq2\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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