document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=183306>Question 183306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that telephone poles that are 18feet tall suspend a telephone wire off the ground along the earth's equator. How much longer than the equator would the length of the telephone wire be? Ignore the sag the diameter of the earth is about 7,926miles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137647 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137647\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let d=diameter of the earth and C the circumference.<BR>\n" );
document.write( "C=pi*d <BR>\n" );
document.write( "The diameter would increase 36' (18*2)<BR>\n" );
document.write( "C=pi(d+36)<BR>\n" );
document.write( "The circumference would increase pi(d+36)-pi*d=pi*d+36pi-pi*d=36pi<BR>\n" );
document.write( "This is 113.09... ft irrespective of what the diameter<BR>\n" );
document.write( "Only 113' more wire would be required.<BR>\n" );
document.write( "The same amount would be required on the moon or on Jupiter (if it were rocky).<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
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