document.write( "Question 183276: 2. grace starts jogging home at 5 km/hr. will leaves 10 minutes later on a bike (from the same place) riding at 15 km/hr. how long will it take will to catch up to grace? \n" ); document.write( "
Algebra.Com's Answer #137629 by stanbon(75887)\"\" \"About 
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Grace starts jogging home at 5 km/hr. Will leaves 10 minutes later on a bike (from the same place) riding at 15 km/hr. How long will it take Will to catch up to Grace?
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\n" ); document.write( "Grace DATA:
\n" ); document.write( "rate = 5 km/h ; time = x hrs ; distance = rt = 5x km
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\n" ); document.write( "Will DATA:
\n" ); document.write( "rate = 15 km/h ; time = (x-(1/6)) hrs ; distance = rt = 15(x-(1/6)) km
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "5x = 15(x - (1/6))\r
\n" ); document.write( "\n" ); document.write( "5x = 15x - (5/2)
\n" ); document.write( "10x = (5/2)
\n" ); document.write( "x = 1/4 hr
\n" ); document.write( "x - (1/6) = (1/4)-(1/6) = (6-4)/24 = 2/24 = 1/12 hr. or 6 minutes\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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