document.write( "Question 183276: 2. grace starts jogging home at 5 km/hr. will leaves 10 minutes later on a bike (from the same place) riding at 15 km/hr. how long will it take will to catch up to grace? \n" ); document.write( "
Algebra.Com's Answer #137628 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! grace starts jogging home at 5 km/hr. will leaves 10 minutes later on a bike (from the same place) riding at 15 km/hr. how long will it take will to catch up to grace? \n" ); document.write( "----------------------- \n" ); document.write( "In 10 minutes, Grace is 5/6 km away. \n" ); document.write( "Will is traveling 10 km/hr wrt (with respect to) Grace. \n" ); document.write( "They will converge in (5/6)/10 hours = 5/60 hours \n" ); document.write( "= 5 minutes. \n" ); document.write( "------------------ \n" ); document.write( "PS stanbon got it right until he said 1/12 hour is 6 minutes. \n" ); document.write( "1/12 hour = 5 minutes. \n" ); document.write( " |