document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=183252>Question 183252</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me and identifies if it is one solution,no solution or infinte solution:<BR>\n" );
document.write( "3x+y=1<BR>\n" );
document.write( "2x-y=-6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137591 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Just add these two equations together:\r<BR>\n" );
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document.write( "3x+y=1<BR>\n" );
document.write( "2x-y=-6\r<BR>\n" );
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document.write( "5x=-5<BR>\n" );
document.write( "x=-1\r<BR>\n" );
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document.write( "Substitute back into the first equation:<BR>\n" );
document.write( "3x+y=1<BR>\n" );
document.write( "3(-1)+Y=1<BR>\n" );
document.write( "-3+y=1<BR>\n" );
document.write( "y=4\r<BR>\n" );
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document.write( "Check in the second equation:<BR>\n" );
document.write( "2x-y=-6<BR>\n" );
document.write( "2(-1)-(4)=-6<BR>\n" );
document.write( "-2-4=-6   It checks!!\r<BR>\n" );
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document.write( "(-1, 4)\r<BR>\n" );
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document.write( "For an easier explanation of this topic, please see my website by clicking on my tutor name \"rapaljer\" anywhere in algebra.com.  On my homepage, look for \"Basic, Intermediate, and College Algebra: One Step at a Time.\"  Select \"Basic Algebra\" and look for the appropriate sections in Chapter 4 of my Basic Algebra book.  It's all FREE, just like algebra.com!!\r<BR>\n" );
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document.write( "R^2 </SPAN>\n" );
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