document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=183148>Question 183148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> together richard and and his brother frank can paint a garage in 2 days. if richard works twice as fats as frank, how long would it take each one to paint the garage alone<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137546 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of time it takes Richard working alone<BR>\n" );
document.write( "Then Richard works at the rate of 1/x garage per day<BR>\n" );
document.write( "And let 2x=amount of time it takes Frank working alone<BR>\n" );
document.write( "Then Frank works at the rate of 1/2x garage per day<BR>\n" );
document.write( "We are told that together Richard and Frank work at the rate of 1/2 garage per day, so:<BR>\n" );
document.write( "1/x+1/2x =1/2 multiply each term by 2x<BR>\n" );
document.write( "2+1=x<BR>\n" );
document.write( "x=3 days---- amount of time it takes Richard working alone<BR>\n" );
document.write( "Then 2x=2*3=6 days---amount of time it takes Frank working alone<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "1/3 +1/6 = 1/2<BR>\n" );
document.write( "2/6 + 1/6=1/2<BR>\n" );
document.write( "1/2=1/2\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );