document.write( "Question 183089: 1.moonshine has 50 liters of a 70% alcohol solution.how many liters of pure alcohol must be added to obtain an 80% alcohol solution
\n" ); document.write( "2.how many kg of pure salt must be added to 20 kg of a 10% salt solution to obtain a 25% salt solution
\n" ); document.write( "3. how much pure acid must be added to 6 ml of a 5% acid solution to produce a 40% acid solution?
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Algebra.Com's Answer #137510 by stanbon(75887)\"\" \"About 
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1.moonshine has 50 liters of a 70% alcohol solution. How many liters of pure alcohol must be added to obtain an 80% alcohol solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.70*50 + 1.00x = 0.80(50+x)
\n" ); document.write( "solve for \"x\"
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\n" ); document.write( "\n" ); document.write( "2.how many kg of pure salt must be added to 20 kg of a 10% salt solution to obtain a 25% salt solution
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\n" ); document.write( "Equation:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.10*20 + 1.00x = 0.25(20+x)
\n" ); document.write( "solve for \"x\"
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\n" ); document.write( "\n" ); document.write( "3. how much pure acid must be added to 6 ml of a 5% acid solution to produce a 40% acid solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.05*6 + 1.00x = 0.40(6+x)
\n" ); document.write( "solve for \"x\"
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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