document.write( "Question 183103This question is from textbook Algebra 2
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document.write( ": If one prime linear Factor of f(x) = x³ + 2x² - 51x + 108 is x + 9,
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document.write( "find the other two prime linear factors. \n" );
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Algebra.Com's Answer #137498 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "f(x) = x³ + 2x² - 51x + 108 \r\n" ); document.write( "\r\n" ); document.write( "Divide x³ + 2x² - 51x + 108 by x + 9, \r\n" ); document.write( "either by long division:\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " x² - 7x + 12 \r\n" ); document.write( "x + 9)x³ + 2x² - 51x + 108 \r\n" ); document.write( " x³ + 9x² \r\n" ); document.write( " -7x² - 51x \r\n" ); document.write( " -7x² - 63x\r\n" ); document.write( " 12x + 108 \r\n" ); document.write( " 12x + 108\r\n" ); document.write( " 0\r\n" ); document.write( " \r\n" ); document.write( "or by, what amounts to the same thing,\r\n" ); document.write( "synthetic division, if you've studied\r\n" ); document.write( "that:\r\n" ); document.write( "\r\n" ); document.write( " -9|1 2 -51 108\r\n" ); document.write( " | -9 63 -108 \r\n" ); document.write( " 1 -7 12 0\r\n" ); document.write( "\r\n" ); document.write( "Either way, thus far you have factored the\r\n" ); document.write( "original cubic polynomial f(x) as:\r\n" ); document.write( "\r\n" ); document.write( "(x + 9)(x² - 7x + 12)\r\n" ); document.write( "\r\n" ); document.write( "Now we can factor the quadratic\r\n" ); document.write( "polynomial in the second parentheses\r\n" ); document.write( "as (x - 3)(x - 4) and the complete\r\n" ); document.write( "factorization of f(x) into prime\r\n" ); document.write( "linear factors is:\r\n" ); document.write( "\r\n" ); document.write( "(x + 9)(x - 3)(x - 4)\r\n" ); document.write( "\r\n" ); document.write( "So the other two prime linear factors of\r\n" ); document.write( "f(x) are (x - 3) and (x - 4).\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |