document.write( "Question 182998: 9. In a certain triangle the measure of one angle is double the measure of a second angle but is 10 degrees less than the measure of the third angle. [The sum of the measures of three interior angles of a triangle is always 180 degrees.] What is the measure of each angle? \n" ); document.write( "
Algebra.Com's Answer #137456 by MathGuyJoe(20)\"\" \"About 
You can put this solution on YOUR website!
Let a, b and c be the 3 angles. Since there are 3 variables, we're gonna need (at least) 3 equations to solve for them. Being a triangle we know:\r
\n" ); document.write( "\n" ); document.write( "Equation 1: \"+a+%2B+b+%2B+c+=+360+\"
\n" ); document.write( "

\n" ); document.write( "\"one angle is double the measure of a second angle\":\r
\n" ); document.write( "\n" ); document.write( "Equation 2: \"+a+=+2b+\"
\n" ); document.write( "

\n" ); document.write( "\"but is 10 degrees less than the measure of the third angle\":\r
\n" ); document.write( "\n" ); document.write( "Equation 3: \"+a+=+c+-+10+\"
\n" ); document.write( "

\n" ); document.write( "Let's re-write equations 2 & 3 in terms of \"a\" so we can substitute them into equation 1.
\n" ); document.write( "Equation 2 can be rewritten as:
\n" ); document.write( "\"+b+=+a%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "Equation 3 can be rewritten as:
\n" ); document.write( "\"+c+=+a+%2B+10+\"
\n" ); document.write( "

\n" ); document.write( "Substituting back into Equation 1 gives us:
\n" ); document.write( "\"+a+%2B+%28a%2F2%29+%2B+%28a+%2B+10%29+=+360+\"\r
\n" ); document.write( "\n" ); document.write( "I prefer not to work with fractions if I can help it, so let's multiply every element, on both sides, by 2:
\n" ); document.write( "\"+2a+%2B+a+%2B+2a+%2B+20+=+720+\"\r
\n" ); document.write( "\n" ); document.write( "Group the a's:
\n" ); document.write( "\"+5a+%2B+20+=+720+\"\r
\n" ); document.write( "\n" ); document.write( "Subtract 20 from both sides:
\n" ); document.write( "\"+5a+=+700+\"\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 5:
\n" ); document.write( "\"+a+=+140+\"
\n" ); document.write( "

\n" ); document.write( "Now we can substitute a back into our \"modified\" Equations 2 & 3 to solve for b & c:
\n" ); document.write( "Equation 2: \"+b+=+a%2F2+\"
\n" ); document.write( "\"+b+=+%28140%29+%2F+2+\"
\n" ); document.write( "\"+b+=+70+\"\r
\n" ); document.write( "\n" ); document.write( "Equation 3: \"+c+=+a+%2B+10+\"
\n" ); document.write( "\"+c+=+%28140%29+%2B+10+\"
\n" ); document.write( "\"+c+=+150+\"
\n" ); document.write( "

\n" ); document.write( "So our angles are 140, 70 and 150.
\n" ); document.write( "

\n" ); document.write( "Hope this helps. ~ Joe
\n" ); document.write( "
\n" );