document.write( "Question 183018: A company has a work force of 21 men that produces two types of top end cabinets.\r
\n" );
document.write( "\n" );
document.write( "Cabinet A is limited to 150 cabinets per day
\n" );
document.write( "Takes 6 person days to produce 100
\n" );
document.write( "Has a profit of 1800 per 100\r
\n" );
document.write( "\n" );
document.write( "Cabinet B is limited to 200 cabinets per day
\n" );
document.write( "Requires 9 person days to produce 100
\n" );
document.write( "Has a profit of 2400 per 100\r
\n" );
document.write( "\n" );
document.write( "I'm really struggling to find the algebraic formula. I've tried spreading the staff across both products and calculating the man hours available and required etc but I just seem to go in circles.
\n" );
document.write( "I know I need 3 Lines on my graph so 3 constraints are required as otherwise the feasible domain wont be found but I'm still going in circles.\r
\n" );
document.write( "\n" );
document.write( "Any help will be greatly appreciated. \n" );
document.write( "
Algebra.Com's Answer #137431 by josmiceli(19441) You can put this solution on YOUR website! Let \n" ); document.write( "Let \n" ); document.write( "Given: \n" ); document.write( " \n" ); document.write( "It takes 6 person-days to make 100 of A \n" ); document.write( "So, it takes 6 persons 1 day to make 100 of A \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The profit is 1800 /100 of A \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-------------------- \n" ); document.write( "It takes 9 person-days to make 100 of B \n" ); document.write( "So, it takes 9 persons 1 day to make 100 of B \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The profit is 2400 / 100 of B \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "I may be wrong with this- it's all I could \n" ); document.write( "come up with \n" ); document.write( " |