document.write( "Question 25602: The length of a rectangular playing field is 5 ft less than twice its width.
\n" ); document.write( "If the perimeter of the playing field is 230 ft, find the length and width of the field.
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Algebra.Com's Answer #13743 by elima(1433)\"\" \"About 
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Let the length of the field = 2w-5
\n" ); document.write( "formula for perimeter;
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "230=2(2w-5+w)
\n" ); document.write( "230=2(3w-5)
\n" ); document.write( "230=6w-10
\n" ); document.write( "230+10=6w
\n" ); document.write( "240=6w
\n" ); document.write( "40=w
\n" ); document.write( "Now that we know w lets get l;
\n" ); document.write( "l=2(40)-5
\n" ); document.write( "l=80-5
\n" ); document.write( "l=75
\n" ); document.write( "So the width=40
\n" ); document.write( "the length = 75
\n" ); document.write( "hope you understand
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