document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=183022>Question 183022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i belive the answer to 1 over 2(x+h) minus 1 over 2x with both being over h is 2h over h is that correct? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137406 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137406\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i believe the answer to 1 over 2(x+h) minus 1 over 2x with both being over h is 2h over h is that correct?<BR>\n" );
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document.write( "[1/[2(x+h)] - [1/2x]]/[h]\r<BR>\n" );
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document.write( "lcd of the numerator is 2x(x+h)\r<BR>\n" );
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document.write( "= [x/lcd - (x+h)/lcd] / [h]\r<BR>\n" );
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document.write( "= [(x-x-h)/lcd]/ h\r<BR>\n" );
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document.write( "= [-h/lcd]/h\r<BR>\n" );
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document.write( "= -1/lcd\r<BR>\n" );
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document.write( "= -1/[2x(x+h)]\r<BR>\n" );
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document.write( "===========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=========================== </SPAN>\n" );
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