document.write( "Question 182961: Write the equation for a line that is perpendicular to the line,
\n" ); document.write( "y = 5x + 10, and goes through the point (8, -1).
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Algebra.Com's Answer #137365 by nerdybill(7384)\"\" \"About 
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y = 5x + 10, and goes through the point (8, -1).
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\n" ); document.write( "The \"slope-intercept\" form of any line is:
\n" ); document.write( "y = mx + b
\n" ); document.write( "where
\n" ); document.write( "m is slope
\n" ); document.write( "b is the y-intercept
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\n" ); document.write( "This is exactly the form you equation was given:
\n" ); document.write( "y = 5x + 10
\n" ); document.write( "(slope is 5)
\n" ); document.write( "Now, we know our NEW line has to have a slope that is the \"negative reciprocal\" for it to be perpendicular:
\n" ); document.write( "Let m = our new slope
\n" ); document.write( "then
\n" ); document.write( "5m = -1
\n" ); document.write( "m = -1/5 (slope of our NEW line)
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\n" ); document.write( "The NEW slope along with the supplied point of (8, -1) can be stuffed into the \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x-x1)
\n" ); document.write( "y - (-1) = (-1/5)(x-8)
\n" ); document.write( "y + 1 = (-1/5)x + 8/5
\n" ); document.write( "y = (-1/5)x + 8/5 - 1
\n" ); document.write( "y = (-1/5)x + 8/5 - 5/5
\n" ); document.write( "y = (-1/5)x + 3/5 (this is what they're looking for)\r
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