document.write( "Question 182957: 5x^4-35x³-90x² \n" ); document.write( "
Algebra.Com's Answer #137354 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming that you want to factor.\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E4-35x%5E3-90x%5E2\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2%28x%5E2-7x-18%29\" Factor out the GCF \"5x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's focus on the inner expression \"x%5E2-7x-18\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"x%5E2-7x-18\", we can see that the first coefficient is \"1\", the second coefficient is \"-7\", and the last term is \"-18\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last term \"-18\" to get \"%281%29%28-18%29=-18\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-18\" (the previous product) and add to the second coefficient \"-7\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-18\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-18\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,6,9,18\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-6,-9,-18\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-18\".\r
\n" ); document.write( "\n" ); document.write( "1*(-18)
\n" ); document.write( "2*(-9)
\n" ); document.write( "3*(-6)
\n" ); document.write( "(-1)*(18)
\n" ); document.write( "(-2)*(9)
\n" ); document.write( "(-3)*(6)\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"-7\":\r
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First NumberSecond NumberSum
1-181+(-18)=-17
2-92+(-9)=-7
3-63+(-6)=-3
-118-1+18=17
-29-2+9=7
-36-3+6=3
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"2\" and \"-9\" add to \"-7\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"2\" and \"-9\" both multiply to \"-18\" and add to \"-7\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"-7x\" with \"2x-9x\". Remember, \"2\" and \"-9\" add to \"-7\". So this shows us that \"2x-9x=-7x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bhighlight%282x-9x%29-18\" Replace the second term \"-7x\" with \"2x-9x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B2x%29%2B%28-9x-18%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B2%29%2B%28-9x-18%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B2%29-9%28x%2B2%29\" Factor out \"9\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-9%29%28x%2B2%29\" Combine like terms. Or factor out the common term \"x%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E2-7x-18\" factors to \"%28x-9%29%28x%2B2%29\".\r
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\n" ); document.write( "\n" ); document.write( "So our expression goes from \"5x%5E2%28x%5E2-7x-18%29\" and factors further to \"5x%5E2%28x-9%29%28x%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"5x%5E4-35x%5E3-90x%5E2\" completely factors to \"5x%5E2%28x-9%29%28x%2B2%29\"\r
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