document.write( "Question 182924: 9. The area of a rectangle is 45 square cm. If the length is 4 cm greater than the width, what are the dimension of the rectangle? \r
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Algebra.Com's Answer #137343 by checkley77(12844)\"\" \"About 
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L=W+4
\n" ); document.write( "AREA=LW
\n" ); document.write( "45=(W+4)W
\n" ); document.write( "45=W^2+4W
\n" ); document.write( "W^2+4W-45=0
\n" ); document.write( "(W+9)(W-5)=0
\n" ); document.write( "W-5=0
\n" ); document.write( "W=5 ANS FOR THE WIDTH.
\n" ); document.write( "L=5+4=9 FOR THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "5*9=45
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