document.write( "Question 182924: 9. The area of a rectangle is 45 square cm. If the length is 4 cm greater than the width, what are the dimension of the rectangle? \r
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Algebra.Com's Answer #137343 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+4 \n" ); document.write( "AREA=LW \n" ); document.write( "45=(W+4)W \n" ); document.write( "45=W^2+4W \n" ); document.write( "W^2+4W-45=0 \n" ); document.write( "(W+9)(W-5)=0 \n" ); document.write( "W-5=0 \n" ); document.write( "W=5 ANS FOR THE WIDTH. \n" ); document.write( "L=5+4=9 FOR THE LENGTH. \n" ); document.write( "PROOF \n" ); document.write( "5*9=45 \n" ); document.write( " |