document.write( "Question 182862: hiw do i solve and check for extraneous roots? \r
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document.write( "sqrt(a-1)-5=1 \n" );
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Algebra.Com's Answer #137324 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "How do I solve and check for extraneous roots? \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 5 to both sides:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Square both sides:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Do the arithmetic. If it is a true statement, the root is valid. If not it is extraneous.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |