document.write( "Question 182910: Lean made a scale drawing design for a tile floor. It measured 9 inches in length and 15 inches in width. The actual width of the tile floor will be 75 inches. If Leah uses 3-inch square tiles to tile the floor, and the floor is proportional to her drawing, how many tiles will she need? \n" ); document.write( "

Algebra.Com's Answer #137320 by josmiceli(19441) $\"\"$ $\"About$

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In words:
\n" ); document.write( "(width of floor on drawing) / (actual width of floor) =
\n" ); document.write( "(width of tile on drawing) / (actual width of tile)
\n" ); document.write( "Now I'll plug in numbers that are given:
\n" ); document.write( " $\"15%2F75+=+x%2F3\"$
\n" ); document.write( "Multiply both sides by $\"75\"$
\n" ); document.write( " $\"15+=+25x\"$
\n" ); document.write( " $\"x+=+.6\"$
\n" ); document.write( "On the drawing, a tile is .6 x .6 in2
\n" ); document.write( "How many of these tiles on the drawing does it take to cover
\n" ); document.write( "9 in x 15 in ?
\n" ); document.write( " $\"9%2F.6+=+15\"$ in
\n" ); document.write( " $\"15%2F.6+=+25\"$ in
\n" ); document.write( "The number of tiles on the drawing is $\"15%2A25+=+375\"$
\n" ); document.write( "She will need 375 tiles -answer
\n" ); document.write( "check answer:
\n" ); document.write( "The actual tiles are 3 in x 3 in = 9 in2
\n" ); document.write( "375 tiles x 9 in2 / tile = 3375 in2
\n" ); document.write( "Now what is the actual area of the floor?
\n" ); document.write( "(length of floor on drawing) / (actual length of floor) =
\n" ); document.write( "(length of tile on drawing) / (actual length of tile)
\n" ); document.write( " $\"9%2Fy+=+.6%2F3\"$
\n" ); document.write( " $\"27+=+.6y\"$
\n" ); document.write( " $\"y+=+45\"$ in
\n" ); document.write( "The area of the floor is $\"xy+=+45%2A75\"$
\n" ); document.write( " $\"45%2A75+=+3375\"$ in2
\n" ); document.write( "OK \n" ); document.write( "

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