document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=182915>Question 182915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If decreasing  y by 40 percent, then increasing that by 130 percent gives you 966, what is the value of y ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137313 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137313\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     If decreasing y by 40 percent, then increasing that by 130 percent gives you 966, what is the value of y ?<BR>\n" );
document.write( ".<BR>\n" );
document.write( "(y-.40y) + 1.3(y-.40y) = 966<BR>\n" );
document.write( "(y -.40y)(1 + 1.3) = 966<BR>\n" );
document.write( "(y -.40y)(2.3) = 966<BR>\n" );
document.write( "(y -.40y) = 966/(2.3)<BR>\n" );
document.write( "y(1 -.40) = 420<BR>\n" );
document.write( "y(.60) = 420<BR>\n" );
document.write( "y = 700 </SPAN>\n" );
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