document.write( "Question 182797: Mara's father is 12 years older than twice her age. If last year he was exactly three times her age, how old are each now? \n" ); document.write( "
Algebra.Com's Answer #137298 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let M = Mara's age now \n" ); document.write( "Let F = Father's age now \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( "\"Mara's father is 12 years older than twice her age.\" \n" ); document.write( "F = 2M + 12 \n" ); document.write( ": \n" ); document.write( "\" If last year he was exactly three times her age,\" \n" ); document.write( "F - 1 = 3M \n" ); document.write( "F = 3M + 1 \n" ); document.write( ": \n" ); document.write( "how old are each now? \n" ); document.write( ": \n" ); document.write( "Substitute (2M+12) for F in the above equation: \n" ); document.write( "2M + 12 = 3M + 1 \n" ); document.write( "12 - 1 = 3M - 2M \n" ); document.write( "M = 11 is Mara's present age \n" ); document.write( "then \n" ); document.write( "2(11) + 12 = 34 yrs is Father's present age \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in the statement: \n" ); document.write( "\"last year he was exactly three times her age,\" \n" ); document.write( "34 - 1 = 3(11) \n" ); document.write( " |