document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=25605>Question 25605</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the surface area of a square pyramid with a base of 2 yds and a slant ht of 2 yds. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13729 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13729\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Each triangle has area = (1/2)*base*height<BR>\n" );
document.write( "triangle area = (1/2)*2*2<BR>\n" );
document.write( "triangle area = 2 yds^2\r<BR>\n" );
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document.write( "There are 4 triangles, so their combined area is 8 yds^2\r<BR>\n" );
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document.write( "Base is a square, whose area is 2*2 --> 4yds^2\r<BR>\n" );
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document.write( "To total SA = 12yds^2\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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