document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=182893>Question 182893</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is a quesion of two step equations.\r<BR>\n" );
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document.write( "   The perimeter of a triangle is 51cm.The lenghts of its sides are sonsecutive odd integers.find the lenghts of all three sides. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137285 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137285\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the first odd number, then x+2 is the next consecutive odd number and x+4 is the next one after that. so...<BR>\n" );
document.write( "x+(x+2)+(x+4) = 51 Combine like-terms on the left.<BR>\n" );
document.write( "3x+6 = 51 Subtract 6 from both sides.<BR>\n" );
document.write( "3x = 45 Divide both sides by 3.<BR>\n" );
document.write( "x = 15, x+2 = 17, and x+4 = 19<BR>\n" );
document.write( "The lengths of the three sides are:<BR>\n" );
document.write( "15cm, 17cm, and 19cm.<BR>\n" );
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