document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=182776>Question 182776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Method of Elimination.<BR>\n" );
document.write( "9. Liz works at ballpark selling bottled water. She sells 37 bottles in one shift. The large bottles sell for $5 each and the small bottles sell for $3 each. At the end of one game, she has taken in $131.<BR>\n" );
document.write( "a) How many large bottles did Liz sell?<BR>\n" );
document.write( "b) How many small bottles did she sell?<BR>\n" );
document.write( "Please and thank you very much </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137230 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137230\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 9. Liz works at ballpark selling bottled water. She sells 37 bottles in one shift. The large bottles sell for $5 each and the small bottles sell for $3 each. At the end of one game, she has taken in $131.<BR>\n" );
document.write( "a) How many large bottles did Liz sell?<BR>\n" );
document.write( "b) How many small bottles did she sell?<BR>\n" );
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document.write( "let call the number of large and small bottles sold L and S, respectively<BR>\n" );
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document.write( "L+S=37...........eq 1<BR>\n" );
document.write( "5L+3S=131........eq 2<BR>\n" );
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document.write( "multiply eq 1 by -3 and add the two equations together...<BR>\n" );
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document.write( "-3(L+S=37)=-3L-3S=-111<BR>\n" );
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document.write( "-3L-3S=-111......eq 1 revised<BR>\n" );
document.write( "5L+3S=131........eq 2<BR>\n" );
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document.write( "adding equations together, we can see that the S terms are eliminated because <BR>\n" );
document.write( "-3S+3S=0. we are left with -3L+5L=-111+131<BR>\n" );
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document.write( "2L=20<BR>\n" );
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document.write( "a)<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28L=10%29 ALIGN=MIDDLE  ALT=\"highlight%28L=10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >number of Large bottles sold<BR>\n" );
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document.write( "take L's found value and plug it back into any numbered equation. I will use eq2<BR>\n" );
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document.write( "5(10)+3S=131<BR>\n" );
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document.write( "3S=81<BR>\n" );
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document.write( "b)<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28S=27%29 ALIGN=MIDDLE  ALT=\"highlight%28S=27%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >number of small bottles sold </SPAN>\n" );
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