document.write( "Question 182723: You have a cube of gold. Your friend (even though she may not be your friend much longer) has a cube of gold that is twice as long (and wide and high). Your friend's cube weights [ ] as much as yours, and it has [ ] times the surface area. You also have a spherical diamond. Your friend has a spherical diamond of twice the diameter of yours. Your friend's cube weights [ ] as much as yours, and it has [ ] the surface area. \n" ); document.write( "
Algebra.Com's Answer #137196 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The the weights of two solid masses of similar material are proportional to their volumes.\r
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\n" ); document.write( "\n" ); document.write( "The volume of your cube, of edge length s is given by:\r
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\n" ); document.write( "\n" ); document.write( "Since the side length of the larger cube is 2s, the volume of the larger cube must be:\r
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\n" ); document.write( "\n" ); document.write( "So your friend's cube has 8 times the volume and therefore weighs 8 times as much as yours.\r
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\n" ); document.write( "\n" ); document.write( "The surface area of a cube of edge length s is found by considering that a cube has 6 faces, each of which has an area , therefore the total surface area of your cube is:\r
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\n" ); document.write( "\n" ); document.write( "And the total surface area of your friend's cube is:\r
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\n" ); document.write( "\n" ); document.write( "And your friend's cube has 4 times the surface area as yours.\r
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\n" ); document.write( "\n" ); document.write( "The problem with the sphere is done in the same fashion. The formulas for volume and surface area for a sphere are:\r
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\n" ); document.write( "\n" ); document.write( "Hint: If your friend's sphere has twice the diameter, it also has twice the radius.\r
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