document.write( "Question 182706This question is from textbook
\n" ); document.write( ": how do I solve this equation? I have to find the real roots for \"y%5E%28-2%29-2%2Fy+%2B2=0\" \n" ); document.write( "
Algebra.Com's Answer #137193 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Multiply thru by y^2 to get
\n" ); document.write( "\"1+-+2y+%2B+2y%5E2+=+0\"
\n" ); document.write( "Now use quadratic equation to solve
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ay%5E2%2Bby%2Bc=0\" (in our case \"2y%5E2%2B-2y%2B1+=+0\") has the following solutons:
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\n" ); document.write( " \"y%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-2%29%5E2-4%2A2%2A1=-4\".
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\n" ); document.write( " The discriminant -4 is less than zero. That means that there are no solutions among real numbers.

\n" ); document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

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\n" ); document.write( " In the field of imaginary numbers, the square root of -4 is + or - \"sqrt%28+4%29+=+2\".
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\n" ); document.write( " The solution is \"y%5B12%5D+=+%28--2%2B-+i%2Asqrt%28+-4+%29%29%2F2%5C2+=++%28--2%2B-+i%2A2%29%2F2%5C2+\"
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\n" ); document.write( " Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B-2%2Ax%2B1+%29\"
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