document.write( "Question 182670: Please help, thank you very much. Also please try to guide me along with your answer, thank you!\r
\n" ); document.write( "\n" ); document.write( "The tens digit of a two-digit number is 6 more than the ones digit. The sum of the number, and the number formed by reversing the digits is 88. Find the number.
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Algebra.Com's Answer #137159 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The tens digit of a two-digit number is 6 more than the ones digit. The sum of the number, and the number formed by reversing the digits is 88. Find the number.
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\n" ); document.write( "Let the number be 10t+u. \"t\" is the tens digit; \"u\" is the units digit.
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\n" ); document.write( "Equations:
\n" ); document.write( "t = u + 6
\n" ); document.write( "10t+u + 10u+t = 88
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\n" ); document.write( "Rearrange:
\n" ); document.write( "t = u + 6
\n" ); document.write( "11t + 11u = 88
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\n" ); document.write( "Simplify
\n" ); document.write( "t - u = 6
\n" ); document.write( "t + u = 8
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\n" ); document.write( "Add to solve for \"t\":
\n" ); document.write( "2t = 14
\n" ); document.write( "t = 7 (the tens digit)
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\n" ); document.write( "Since t+u = 8, u = 1
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\n" ); document.write( "The number is 8*10+1 = 81
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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