document.write( "Question 25541: I have an assignment due on arithmetic series of numbers. I have been studying my book and can't seem to figure out what I am supposed to do to make or solve the equations. Is there anyway you can help? Thank you in advance.\r
\n" ); document.write( "\n" ); document.write( "Use the arithmetic series of numbers 1,3,5,7,9,...to find the following:\r
\n" ); document.write( "\n" ); document.write( "What is d, the difference between any 2 numbers?\r
\n" ); document.write( "\n" ); document.write( "Using the formula for the nth term of an arithmetic series, what is 101st term?\r
\n" ); document.write( "\n" ); document.write( "Using the formula for the sum of an arithmetic series, what is the sum of the first 20 terms?\r
\n" ); document.write( "\n" ); document.write( "Using the formula for the sum of an arithmetic series, what is the sum of the first 30 terms?\r
\n" ); document.write( "\n" ); document.write( "What observation can you make about these sums of this series(HINT: It would be beneficial to find a few more sums like the sum of the first 2, then the first 3 etc.)?\r
\n" ); document.write( "\n" ); document.write( "I know it seems like a lot but it really is just one problem broken down into several sections. I have no idea how to so this so I would be VERY thankful for any help you can give me.
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Algebra.Com's Answer #13715 by askmemath(368)\"\" \"About 
You can put this solution on YOUR website!
\"d\" is the common difference between any 2 consecutive numbers
\n" ); document.write( "In this case the sequence is 1,3,5,7........
\n" ); document.write( "So the difference becomes 3-1= 5-3 = 7-5 = 2\r
\n" ); document.write( "\n" ); document.write( "Now every arithmetic series is represented by \"a%2B%28n-1%29d\" where a is the first term and d the common difference
\n" ); document.write( "n-1 is the nth term\r
\n" ); document.write( "\n" ); document.write( "For the given series, a = 1 since the series begins with 1 and d = 2
\n" ); document.write( "The 1st term is 1
\n" ); document.write( "2nd term is 3
\n" ); document.write( "So the 101st term becomes 1+(101-1)2 = 1+200 = 201\r
\n" ); document.write( "\n" ); document.write( "Sum to n terms is given by \"%28n%2F2%29%2AFirst+Term+%2B+Last+Term\" where n is the number of terms.
\n" ); document.write( "Please solve this on your own as I have already shown you above how to find the last term. Again you can the find the sum to the first 30 terms with the same formula.\r
\n" ); document.write( "\n" ); document.write( "Adding the first two numbers or the first three or so on, you will find that the sum is always an Even Number.
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