document.write( "Question 182662: 1/5x+y=6/5
\n" ); document.write( "1/10x+1/3y=5/6\r
\n" ); document.write( "\n" ); document.write( "Using elimination, not substitution.
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Algebra.Com's Answer #137145 by MathGuyJoe(20)\"\" \"About 
You can put this solution on YOUR website!
Given the equations:
\n" ); document.write( "\"+%281%2F5%29x+%2B+y+=+6%2F5+\"
\n" ); document.write( "\"+%281%2F10%29x+%2B+%281%2F3%29y+=+5%2F6+\"
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\n" ); document.write( "By rule, you can multiply both sides of an equation by any constant without changing the result, so let's do this to both equations to get rid of the fractions. We'll multiply each element in the top equation by 5 and we'll multiply each element in the bottom equation by 30 (the least common multiple). That leaves us:
\n" ); document.write( "\"+x+%2B+5y+=+6+\"
\n" ); document.write( "\"+3x+%2B+10y+=+25+\"
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\n" ); document.write( "Now that we don't have any fractions, let's get to work. In order to eliminate a variable, we need to choose a multiplier for one of the equations that, when added to the other equation, will cancel out either the x or the y. Let's cancel out the y's by multiplying the top equation by -2. That gives us:
\n" ); document.write( "\"+-2x+-+10y+=+-12+\"
\n" ); document.write( "Now adding that to our second equation:
\n" ); document.write( "\"+3x+%2B+10y+=+25+\"
\n" ); document.write( "Gives us:
\n" ); document.write( "\"+%28-2x+%2B+3x%29+%2B+%28-10y+%2B+10y%29+=+-12+%2B+25+\"
\n" ); document.write( "\"+x+=+13+\"
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\n" ); document.write( "Plugging 13 back into \"+x+%2B+5y+=+6+\" in place of x gives us:
\n" ); document.write( "\"+%2813%29+%2B+5y+=+6+\"
\n" ); document.write( "\"+5y+=+-7+\"
\n" ); document.write( "\"+y+=+-7%2F5+\"
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\n" ); document.write( "So our final answers are x = 13 and y = -7/5.
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\n" ); document.write( "For confirmation, take these x and y values and plug them back into each of the original equations -- after a bunch of fraction work, you'll find the answers check out. =)
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\n" ); document.write( "Hope this helps. ~ Joe
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